If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( y )
y = 0
y^-4 = 0
y = 0
y = 0
y^-4 = 0
y^-4 = 0
1*y^-4 = 0 // : 1
y^-4 = 0
y należy do O
y in (-oo:0) U (0:+oo)
(y^3)/(y^-4) = 0
1*y^7 = 0 // : 1
y^7 = 0
y = 0
y in { 0}
y belongs to the empty set
| (9-x)(4x+7)=0 | | d/3=-84 | | -32x^2+3025x+363000=0 | | 4x-23=-3(x+3) | | -32x^2+3025x+665500=0 | | 3x+7y-3=0 | | 36/x=12/2 | | -3+3u=-24 | | .6=.3+x-.15 | | (3)/(-4x-2) | | X/2-3/4=x/3-5/6 | | x(4)-5=3 | | x+3y+35=0 | | 4x-6x+5-1=2x+3x-7+4 | | 7y-5(4y-5)= | | 90x-(9/2)x^2=0 | | (2/3)p=18 | | -17a=391 | | x/4-117/4x=1 | | x+(2*x)=145 | | x-0.28x= | | 0.6(x-6)=9.0 | | 6y-8-y=19-9y | | 5b-20/8b-32 | | -5y-7y=-13-9 | | 3a-13+4a=7a+1 | | 3[5-3(4-9)]-5=5[3(5q-4)+2]-26 | | x-0.4x=102 | | .1243f+1.554=.1863P | | y=ln(4e^2x) | | 18p+2v=3d | | (10x^3)/(xy^7)(2x^5y^6)/(5xy^3) |